这道题比较简单，求众数，并且一定存在 策略：遇到相同的数+1,遇到不同的数-1，当前数目是0，那么就重置新的众数 因为必定有一个众数，那么++--后，剩余的那个数就是我们要求的
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2016-08-03 09:49:00
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/*素数时间限制：3000 ms | 内存限制：65535 KB难度：1描述走进世博园某信息通信馆，参观者将获得前所未有的尖端互动终端参与
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2022-08-30 15:46:09
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如果在AB的1769系统里需要走Modbus RTU通讯的话就需要Prosoft的1769系列的机架式产品，之前的项目用的是老型号MVI69-MCM，那么新项目就会用MVI69E-MBS这个型号。那么模块的通讯拓扑图如下所示：模块往下可以连接仪表，变频器，PLC，电力仪表等等ModbusRTU协议的设备，往上还可以跟DCS,SCADA进行通讯。如果是在之前的老项目中如果是MVI69-MCM这个型号
public class Solution {
public int MajorityElement(int[] nums) {
Dictionary<int, int> dic = new Dictionary<int, int>();
var len = nums.Length;
for (i
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2017-04-19 11:19:00
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和素数距离问题基本类似 那个好像还比这个稍...
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2016-01-31 01:30:00
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和素数距离问题基本类似 那个好像还比这个稍...
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2016-01-31 01:30:00
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You have two tables with referential integrity enforced between them. You need to insert data to the child table first because it is going to be a lon
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2017-12-15 10:31:00
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Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.You may assume that the array is non-empty and the majority element a...
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2021-07-14 15:39:12
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Given an array of sizen, find the majority element. The majority element is the element that appears more than⌊ n/2 ⌋times.You may assume that the arr...
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2015-02-08 23:26:00
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Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the
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2019-01-28 18:23:00
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/*题目要求：Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.You may assume that the array is non-empty and the majority
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2022-02-03 14:04:33
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给定一个大小为 n 的数组 nums ，返回其中的多数元素。多数元素是指在数组中出现次数 大于 ⌊ n/2 ⌋ 的元素。示例 1：输入：nums = [3,2,3]
输出：3示例 2：输入：nums = [2,2,1,1,1,2,2]
输出：2这道题要找出现次数大于N/2的数，我就先对数组排序，从小到大，再用
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2023-08-10 22:36:23
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题目
Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.
You may assume that the array is non-empty and the majority element al
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2024-02-20 13:01:03
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Given an array of size n, find the majority element. The majority element is the element that y element always
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2022-08-23 19:21:03
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https://oj.leetcode.com/problems/majority-element/ public class Solution {
public int majorityElement(int[] num) {
&n
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2015-01-09 16:58:34
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/*题目要求：Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.You may assume that the array is non-empty and the majority
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2021-07-09 14:02:23
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Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the
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2018-09-28 11:57:00
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摩尔投票法，首先将第一个元素设置为候选众数，并记录出现的次数，进行遍历的过程中，每一次出现与候选众数不同的数，其count就-1，若是候选众数，则+1，若是count变为0，则代表当前候选众数已经被消耗完全，选择下一个数作为候选众数，直到完成遍历，最后剩下的众数即为数组中的众数，贴代码 1 clas ...
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2021-09-14 15:37:00
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A #include<bits/stdc++.h> using namespace std; int main(){ int a, b; cin>>a>>b; cout<<a*b<<endl; return 0; } B 为了避免溢出就用 py 写了 import sys n=int(input() ...
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2021-07-16 21:38:00
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题目：Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.You may assume that the array is non-empty and the majority e
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2023-03-07 11:52:15
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