//**四川大学计算机学院 贾钰，外号：编程菜鸟   打发时间方式：ACM**//

Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input
```2
1 2
112233445566778899 998877665544332211```

Sample Output
```Case 1:
1 + 2 = 3```
```Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110```
`下面是我的代码：`
`#include<iostream>#include<string>using namespace std;void main(){    char A[1000],B[1000];    int sum[1001];    int n,i;    while(cin>>n)    {        int index(0),sumindex(0);        for(i=1;i<=n;i++)        {            memset(sum,0,sizeof(sum));            cin>>A>>B;           int index(0),sumindex(0);           for(index=strlen(A)-1,sumindex=1000;index>=0;index--,sumindex--)           {             sum[sumindex]+=A[index]-'0';           }           for(index=strlen(B)-1,sumindex=1000;index>=0;index--,sumindex--)           {                sum[sumindex]+=B[index]-'0';           }          for(sumindex=1000;sumindex!=0;sumindex--)          {             if(sum[sumindex]>9)             {                sum[sumindex-1]+=sum[sumindex]/10;                sum[sumindex]=sum[sumindex]%10;             }          }         for(sumindex=0;sumindex<=1000;sumindex++)         {            if(sum[sumindex]!=0)            {                break;            }         }            if(sumindex=1001)            {                sumindex=1000;            }                    cout<<"Case "<<i<<":"<<endl;        cout<<A<<" + "<<B<<" = ";            sumindex=0;        while(!sum[sumindex])sumindex++;        for(;sumindex<=1000;sumindex++)        {            cout<<sum[sumindex];        }        cout<<endl;        if(i-n){cout<<endl;cout<<endl;}        }        break;    }} `
`有条件的可以将我的代码放到你的编译器上运行一下，注意观察我的运算结果和题目要求，但是我提交的时候显示：Presentation Error`